What is the answer to solvefor a,an=1+n-n^2 ?

The answer to solvefor a,an=1+n-n^2 is a=(1+n-n^2)/n ;\quad n\ne 0

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solvefor a,an=1+n-n^2

solve for

a, an = 1 + n - n^{2}

a = \frac{1 + n - n ^{2}}{n}; n \neq = 0

Solution steps

an = 1 + n - n^{2}

Divide both sides by

n; n \neq = 0

a = \frac{1 + n - n ^{2}}{n}; n \neq = 0

(2 x - 5)^{2} = (x - 6)^{2} + (2 x + 1) (2 x - 9)

x^{2} = \frac{1}{100}

2 x^{2} - 7 x + 3 = 0

a, (a + 2 b) (a - b) = 10

4 x^{2} + 10 x + 3 = 0

What is the answer to solvefor a,an=1+n-n^2 ?
The answer to solvefor a,an=1+n-n^2 is a=(1+n-n^2)/n ;\quad n\ne 0