What are the solutions to the equation 3x^2-20x+17=0 ?

The solutions to the equation 3x^2-20x+17=0 are x= 17/3 ,x=1

Find the zeros of 3x^2-20x+17=0

The zeros of 3x^2-20x+17=0 are x= 17/3 ,x=1

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3 x^{2} - 20 x + 17 = 0

x = \frac{17}{3}, x = 1

Decimal Notation

x = 5.66666 \dots, x = 1

Solution steps

3 x^{2} - 20 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 3 \cdot 17}{2 \cdot 3}

(- 20)^{2} - 4 \cdot 3 \cdot 17 = 14

x_{1, 2} = \frac{- ( - 20 ) \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 14}{2 \cdot 3}, x_{2} = \frac{- ( - 20 ) - 14}{2 \cdot 3}

x = \frac{- ( - 20 ) + 14}{2 \cdot 3} : \frac{17}{3}

x = \frac{- ( - 20 ) - 14}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{17}{3}, x = 1

3 x^{2} - 3 x + 6 = 0

12 x^{2} - 12 x + 2 = 0

x^{2} = 4 \cdot 9

x^{2} + x - 1 = 1

x^{2} - 2 x = 8

What are the solutions to the equation 3x^2-20x+17=0 ?
The solutions to the equation 3x^2-20x+17=0 are x= 17/3 ,x=1
Find the zeros of 3x^2-20x+17=0
The zeros of 3x^2-20x+17=0 are x= 17/3 ,x=1