What are the solutions to the equation -2x^2+2x-2=0 ?

The solutions to the equation -2x^2+2x-2=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2

Find the zeros of -2x^2+2x-2=0

The zeros of -2x^2+2x-2=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2

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- 2 x^{2} + 2 x - 2 = 0

x = \frac{1}{2} - i \frac{3}{2}, x = \frac{1}{2} + i \frac{3}{2}

Solution steps

- 2 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

Simplify

2^{2} - 4 (- 2) (- 2) : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 ( - 2 )}, x_{2} = \frac{- 2 - 2 3 i}{2 ( - 2 )}

x = \frac{- 2 + 2 3 i}{2 ( - 2 )} : \frac{1}{2} - i \frac{3}{2}

x = \frac{- 2 - 2 3 i}{2 ( - 2 )} : \frac{1}{2} + i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{3}{2}, x = \frac{1}{2} + i \frac{3}{2}

- 73 x^{2} + 4600 x = 250 x + 5340

4 x^{3} - 4 x^{2} + x

(z + 5)^{2} = - 9

(- 4 i)^{2}

3 x^{2} + 2 x y

What are the solutions to the equation -2x^2+2x-2=0 ?
The solutions to the equation -2x^2+2x-2=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2
Find the zeros of -2x^2+2x-2=0
The zeros of -2x^2+2x-2=0 are x= 1/2-i(sqrt(3))/2 ,x= 1/2+i(sqrt(3))/2