What are the solutions to the equation 5(x-7)^2+10=190 ?

The solutions to the equation 5(x-7)^2+10=190 are x=13,x=1

Find the zeros of 5(x-7)^2+10=190

The zeros of 5(x-7)^2+10=190 are x=13,x=1

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5 (x - 7)^{2} + 10 = 190

x = 13, x = 1

Solution steps

5 (x - 7)^{2} + 10 = 190

Move

10

to the right side

5 (x - 7)^{2} = 180

Divide both sides by

5

(x - 7)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 36 : x = 13

Solve

x - 7 = - 36 : x = 1

The solutions to the quadratic equation are:

x = 13, x = 1

15 a^{2} - 12 a - 3 = 0

t, t^{2} - 5 v t + 30 v = 0

- 16 t^{2} + 16 t + 320 = 0

x (x + 15) = 1 0^{2}

- x^{2} + 6 x - 3 = 0

What are the solutions to the equation 5(x-7)^2+10=190 ?
The solutions to the equation 5(x-7)^2+10=190 are x=13,x=1
Find the zeros of 5(x-7)^2+10=190
The zeros of 5(x-7)^2+10=190 are x=13,x=1