What are the solutions to the equation -2x^2=x ?

The solutions to the equation -2x^2=x are x=-1/2 ,x=0

Find the zeros of -2x^2=x

The zeros of -2x^2=x are x=-1/2 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} = x

x = - \frac{1}{2}, x = 0

Decimal Notation

x = - 0.5, x = 0

Solution steps

- 2 x^{2} = x

Move

x

to the left side

- 2 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 1}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 1}{2 ( - 2 )} : - \frac{1}{2}

x = \frac{- ( - 1 ) - 1}{2 ( - 2 )} : 0

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 0

y, y^{2} = x (x - 1)^{2}

x^{2} + \frac{5}{4} = \frac{6}{4}

16 x^{2} = 35

X^{2} = 144

a^{2} + 9 a = 0

What are the solutions to the equation -2x^2=x ?
The solutions to the equation -2x^2=x are x=-1/2 ,x=0
Find the zeros of -2x^2=x
The zeros of -2x^2=x are x=-1/2 ,x=0