What are the solutions to the equation 3r^2-16r-12=0 ?

The solutions to the equation 3r^2-16r-12=0 are r=6,r=-2/3

Find the zeros of 3r^2-16r-12=0

The zeros of 3r^2-16r-12=0 are r=6,r=-2/3

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3 r^{2} - 16 r - 12 = 0

r = 6, r = - \frac{2}{3}

Decimal Notation

r = 6, r = - 0.66666 \dots

Solution steps

3 r^{2} - 16 r - 12 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 12) = 20

r_{1, 2} = \frac{- ( - 16 ) \pm 20}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- ( - 16 ) + 20}{2 \cdot 3}, r_{2} = \frac{- ( - 16 ) - 20}{2 \cdot 3}

r = \frac{- ( - 16 ) + 20}{2 \cdot 3} : 6

r = \frac{- ( - 16 ) - 20}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

r = 6, r = - \frac{2}{3}

12 x^{2} - 5 x = 0

x, y^{2} (x^{2} + y^{2}) = 2 x^{2}

x^{2} - 6 x - 11 = 0

x^{2} + 8 x + 5

8 q^{2} - 9 = 12 q - 9

What are the solutions to the equation 3r^2-16r-12=0 ?
The solutions to the equation 3r^2-16r-12=0 are r=6,r=-2/3
Find the zeros of 3r^2-16r-12=0
The zeros of 3r^2-16r-12=0 are r=6,r=-2/3