What are the solutions to the equation 8x^2-2x=0 ?

The solutions to the equation 8x^2-2x=0 are x= 1/4 ,x=0

Find the zeros of 8x^2-2x=0

The zeros of 8x^2-2x=0 are x= 1/4 ,x=0

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8 x^{2} - 2 x = 0

x = \frac{1}{4}, x = 0

Decimal

x = 0.25, x = 0

Solution steps

8 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 8}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 8}

x = \frac{- ( - 2 ) + 2}{2 \cdot 8} : \frac{1}{4}

x = \frac{- ( - 2 ) - 2}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

6 x^{2} + 11 x + 4

\frac{5 x + 10}{10} - 2 = \frac{7 x}{2} - \frac{1 + 3 x}{3} - 4 x

5 x + {2} = 7 x

15 x^{2} + 28 x + 5

15 + c^{2} = 96

What are the solutions to the equation 8x^2-2x=0 ?
The solutions to the equation 8x^2-2x=0 are x= 1/4 ,x=0
Find the zeros of 8x^2-2x=0
The zeros of 8x^2-2x=0 are x= 1/4 ,x=0