What are the solutions to the equation 12^2+8^2=c^2 ?

The solutions to the equation 12^2+8^2=c^2 are c=4sqrt(13),c=-4sqrt(13)

Find the zeros of 12^2+8^2=c^2

The zeros of 12^2+8^2=c^2 are c=4sqrt(13),c=-4sqrt(13)

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1 2^{2} + 8^{2} = c^{2}

c = 413, c = - 413

Decimal Notation

c = 14.42220 \dots, c = - 14.42220 \dots

Solution steps

1 2^{2} + 8^{2} = c^{2}

Switch sides

c^{2} = 1 2^{2} + 8^{2}

Simplify

1 2^{2} + 8^{2} : 208

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 208, c = - 208

208 = 413

- 208 = - 413

c = 413, c = - 413

3 x^{2} - 12 x + 7

3 x^{2} - 12 x + 8

- 2 x^{2} + 5 x + 10 = 0

3 x^{2} - 1 = 14

x^{2} - 18 x + 106 = 0

What are the solutions to the equation 12^2+8^2=c^2 ?
The solutions to the equation 12^2+8^2=c^2 are c=4sqrt(13),c=-4sqrt(13)
Find the zeros of 12^2+8^2=c^2
The zeros of 12^2+8^2=c^2 are c=4sqrt(13),c=-4sqrt(13)