What are the solutions to the equation 5x^2+140=0 ?

The solutions to the equation 5x^2+140=0 are x=2sqrt(7)i,x=-2sqrt(7)i

Find the zeros of 5x^2+140=0

The zeros of 5x^2+140=0 are x=2sqrt(7)i,x=-2sqrt(7)i

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5 x^{2} + 140 = 0

x = 27 i, x = - 27 i

Solution steps

5 x^{2} + 140 = 0

Move

140

to the right side

5 x^{2} = - 140

Divide both sides by

5

x^{2} = - 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 28, x = - - 28

- 28 = 27 i

- - 28 = - 27 i

x = 27 i, x = - 27 i

(2 x - 4) (x + 5) = 0

15 = 8 h^{2} - 2 h

a, z = a^{2} - x^{2} - y^{2}

m^{2} + 16 m - 32 = - 7

4 x^{2} + 3 x = 0

What are the solutions to the equation 5x^2+140=0 ?
The solutions to the equation 5x^2+140=0 are x=2sqrt(7)i,x=-2sqrt(7)i
Find the zeros of 5x^2+140=0
The zeros of 5x^2+140=0 are x=2sqrt(7)i,x=-2sqrt(7)i