What are the solutions to the equation 3-(x-2)^2=7 ?

The solutions to the equation 3-(x-2)^2=7 are x=2i+2,x=-2i+2

Find the zeros of 3-(x-2)^2=7

The zeros of 3-(x-2)^2=7 are x=2i+2,x=-2i+2

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3 - (x - 2)^{2} = 7

x = 2 i + 2, x = - 2 i + 2

Solution steps

3 - (x - 2)^{2} = 7

Move

3

to the right side

- (x - 2)^{2} = 4

Divide both sides by

- 1

(x - 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 4 : x = 2 i + 2

Solve

x - 2 = - - 4 : x = - 2 i + 2

The solutions to the quadratic equation are:

x = 2 i + 2, x = - 2 i + 2

0 = x^{2} - 5 x - 14

8 x^{2} + 6 x - 2 = 0

6 x^{2} = 3 x

5 x^{2} + 75 = 0

- 12 x^{2} - 42 x = 0

What are the solutions to the equation 3-(x-2)^2=7 ?
The solutions to the equation 3-(x-2)^2=7 are x=2i+2,x=-2i+2
Find the zeros of 3-(x-2)^2=7
The zeros of 3-(x-2)^2=7 are x=2i+2,x=-2i+2