What are the solutions to the equation r^2-5r-6=0 ?

The solutions to the equation r^2-5r-6=0 are r=6,r=-1

Find the zeros of r^2-5r-6=0

The zeros of r^2-5r-6=0 are r=6,r=-1

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r^{2} - 5 r - 6 = 0

r = 6, r = - 1

Solution steps

r^{2} - 5 r - 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

r_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, r_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

r = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

r = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

r = 6, r = - 1

5 x^{2} + 170 = 60 x

x, x^{2} - x y + y^{2} = 6

x, x^{2} - x y + y^{2} = 2

10 0^{2} + x^{2} = 20 0^{2}

- 0.3 x^{2} + 12 x = 0

What are the solutions to the equation r^2-5r-6=0 ?
The solutions to the equation r^2-5r-6=0 are r=6,r=-1
Find the zeros of r^2-5r-6=0
The zeros of r^2-5r-6=0 are r=6,r=-1