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What are the solutions to the equation x=10(4.7-x)^2 ?
The solutions to the equation x=10(4.7-x)^2 are x=(95+3sqrt(21))/(20),x=(95-3sqrt(21))/(20)Find the zeros of x=10(4.7-x)^2
The zeros of x=10(4.7-x)^2 are x=(95+3sqrt(21))/(20),x=(95-3sqrt(21))/(20)