What are the solutions to the equation 16x^2=-35 ?

The solutions to the equation 16x^2=-35 are x=(sqrt(35))/4 i,x=-(sqrt(35))/4 i

Find the zeros of 16x^2=-35

The zeros of 16x^2=-35 are x=(sqrt(35))/4 i,x=-(sqrt(35))/4 i

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16 x^{2} = - 35

x = \frac{35}{4} i, x = - \frac{35}{4} i

Solution steps

16 x^{2} = - 35

Divide both sides by

16

x^{2} = - \frac{35}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{35}{16}, x = - - \frac{35}{16}

- \frac{35}{16} = \frac{35}{4} i

- - \frac{35}{16} = - \frac{35}{4} i

x = \frac{35}{4} i, x = - \frac{35}{4} i

x^{2} + 5 x = 21

(x - 4) (x - 3) = 0

- x = - 6 x^{2} + 1

x^{2} - x = - 7

x^{2} - x - \frac{1}{4} = 0

What are the solutions to the equation 16x^2=-35 ?
The solutions to the equation 16x^2=-35 are x=(sqrt(35))/4 i,x=-(sqrt(35))/4 i
Find the zeros of 16x^2=-35
The zeros of 16x^2=-35 are x=(sqrt(35))/4 i,x=-(sqrt(35))/4 i