What are the solutions to the equation v^2-7v-5=-6v-6v ?

The solutions to the equation v^2-7v-5=-6v-6v are v=(-5+3sqrt(5))/2 ,v=(-5-3sqrt(5))/2

Find the zeros of v^2-7v-5=-6v-6v

The zeros of v^2-7v-5=-6v-6v are v=(-5+3sqrt(5))/2 ,v=(-5-3sqrt(5))/2

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v^{2} - 7 v - 5 = - 6 v - 6 v

v = \frac{- 5 + 3 5}{2}, v = \frac{- 5 - 3 5}{2}

Decimal Notation

v = 0.85410 \dots, v = - 5.85410 \dots

Solution steps

v^{2} - 7 v - 5 = - 6 v - 6 v

Refine

v^{2} - 7 v - 5 = - 12 v

Move

12 v

to the left side

v^{2} + 5 v - 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 5) = 35

v_{1, 2} = \frac{- 5 \pm 3 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 5 + 3 5}{2 \cdot 1}, v_{2} = \frac{- 5 - 3 5}{2 \cdot 1}

v = \frac{- 5 + 3 5}{2 \cdot 1} : \frac{- 5 + 3 5}{2}

v = \frac{- 5 - 3 5}{2 \cdot 1} : \frac{- 5 - 3 5}{2}

The solutions to the quadratic equation are:

v = \frac{- 5 + 3 5}{2}, v = \frac{- 5 - 3 5}{2}

y^{2} = - 10

4 x^{2} + 8 x = 0

2 x^{2} + x = 2 x + 6

x^{2} + 8 x - 12

(m - 4)^{2} + (m - 7)^{2} = 15

What are the solutions to the equation v^2-7v-5=-6v-6v ?
The solutions to the equation v^2-7v-5=-6v-6v are v=(-5+3sqrt(5))/2 ,v=(-5-3sqrt(5))/2
Find the zeros of v^2-7v-5=-6v-6v
The zeros of v^2-7v-5=-6v-6v are v=(-5+3sqrt(5))/2 ,v=(-5-3sqrt(5))/2