What are the solutions to the equation 14x^2+35x=0 ?

The solutions to the equation 14x^2+35x=0 are x=0,x=-5/2

Find the zeros of 14x^2+35x=0

The zeros of 14x^2+35x=0 are x=0,x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

14 x^{2} + 35 x = 0

x = 0, x = - \frac{5}{2}

Decimal Notation

x = 0, x = - 2.5

Solution steps

14 x^{2} + 35 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 14 \cdot 0}{2 \cdot 14}

3 5^{2} - 4 \cdot 14 \cdot 0 = 35

x_{1, 2} = \frac{- 35 \pm 35}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- 35 + 35}{2 \cdot 14}, x_{2} = \frac{- 35 - 35}{2 \cdot 14}

x = \frac{- 35 + 35}{2 \cdot 14} : 0

x = \frac{- 35 - 35}{2 \cdot 14} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{2}

x^{2} + 8 x + 10

x^{2} + 8 x + 14

x^{2} + 8 x + 16

x^{2} + 8^{2} = 1 2^{2}

x, 3 x^{2} - 2 x - 5 = 0

What are the solutions to the equation 14x^2+35x=0 ?
The solutions to the equation 14x^2+35x=0 are x=0,x=-5/2
Find the zeros of 14x^2+35x=0
The zeros of 14x^2+35x=0 are x=0,x=-5/2