What are the solutions to the equation y^2+6y=7 ?

The solutions to the equation y^2+6y=7 are y=1,y=-7

Find the zeros of y^2+6y=7

The zeros of y^2+6y=7 are y=1,y=-7

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y^{2} + 6 y = 7

y = 1, y = - 7

Solution steps

y^{2} + 6 y = 7

Move

7

to the left side

y^{2} + 6 y - 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

y_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 8}{2 \cdot 1}, y_{2} = \frac{- 6 - 8}{2 \cdot 1}

y = \frac{- 6 + 8}{2 \cdot 1} : 1

y = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = 1, y = - 7

y^{2} + 6 y = 0

x - x^{2} + 2 = 0

(x^{2} + 4) 2 - 11 (x^{2} + 4) + 24 = 0

t^{2} + 12 t + 36 = 0

4 p^{2} - 12 p + 3 = 0

What are the solutions to the equation y^2+6y=7 ?
The solutions to the equation y^2+6y=7 are y=1,y=-7
Find the zeros of y^2+6y=7
The zeros of y^2+6y=7 are y=1,y=-7