-3<-1+x\lor (-5)/6 x>2

Solution

- 3 < - 1 + x or \frac{- 5}{6} x > 2

x < - \frac{12}{5} or x > - 2

Interval Notation

(- \infty, - \frac{12}{5}) \cup (- 2, \infty)

Decimal Notation

x < - 2.4 or x > - 2

Solution steps

- 3 < - 1 + x or \frac{- 5}{6} x > 2

- 3 < - 1 + x : x > - 2

\frac{- 5}{6} x > 2 : x < - \frac{12}{5}

Combine the intervals

x > - 2 or x < - \frac{12}{5}

Merge Overlapping Intervals

x < - \frac{12}{5} or x > - 2

x^{2} - 20 x + 91

8 (- 2 + 3)^{\frac{5}{6}}

∣ x - 3 ∣ + ∣ x + 2 ∣ < 13

5 x = - 3 x - 24

3 x + 9 = 0

What is -3<-1+x\lor (-5)/6 x>2 ?
The solution to -3<-1+x\lor (-5)/6 x>2 is x<-12/5 \lor x>-2