What are the solutions to the equation 20^2+x^2=29^2 ?

The solutions to the equation 20^2+x^2=29^2 are x=21,x=-21

Find the zeros of 20^2+x^2=29^2

The zeros of 20^2+x^2=29^2 are x=21,x=-21

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 0^{2} + x^{2} = 2 9^{2}

x = 21, x = - 21

Solution steps

2 0^{2} + x^{2} = 2 9^{2}

Move

2 0^{2}

to the right side

x^{2} = 441

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 441, x = - 441

441 = 21

- 441 = - 21

x = 21, x = - 21

x^{2} + (x + 10)^{2} = 5 0^{2}

5 x^{2} + x + 7 = - 2 x^{2} + 8 x - 1

x^{2} - 6 x - 25 = 0

- 3 x^{2} + 7 x = 0

1 + 5 + 9 + 4 n - 3 = n (2 n - 1)

What are the solutions to the equation 20^2+x^2=29^2 ?
The solutions to the equation 20^2+x^2=29^2 are x=21,x=-21
Find the zeros of 20^2+x^2=29^2
The zeros of 20^2+x^2=29^2 are x=21,x=-21