What are the solutions to the equation 5y^2=-25y ?

The solutions to the equation 5y^2=-25y are y=0,y=-5

Find the zeros of 5y^2=-25y

The zeros of 5y^2=-25y are y=0,y=-5

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5 y^{2} = - 25 y

y = 0, y = - 5

Solution steps

5 y^{2} = - 25 y

Move

25 y

to the left side

5 y^{2} + 25 y = 0

Factor

5 y^{2} + 25 y : 5 y (y + 5)

5 y (y + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y + 5 = 0

Solve

y + 5 = 0 : y = - 5

The solutions to the quadratic equation are:

y = 0, y = - 5

x + 32 = \frac{1}{7} (x + 7) (x - 4)

- 1 x^{2} + 3 x - 10 = 0

- 4 = \frac{5 x ^{2} \cdot 7}{2 ( a + 3 )}

- (x - 5)^{2} + 25 = 0

5 x^{2} + 8 x = - 3

What are the solutions to the equation 5y^2=-25y ?
The solutions to the equation 5y^2=-25y are y=0,y=-5
Find the zeros of 5y^2=-25y
The zeros of 5y^2=-25y are y=0,y=-5