What are the solutions to the equation x^2-2(x-1)=0 ?

The solutions to the equation x^2-2(x-1)=0 are x=1+i,x=1-i

Find the zeros of x^2-2(x-1)=0

The zeros of x^2-2(x-1)=0 are x=1+i,x=1-i

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x^{2} - 2 (x - 1) = 0

x = 1 + i, x = 1 - i

Solution steps

x^{2} - 2 (x - 1) = 0

Expand

x^{2} - 2 (x - 1) : x^{2} - 2 x + 2

x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

x = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

x = 1 + i, x = 1 - i

x^{2} + (x + 3)^{2} = 9

4 x^{2} - 4 x - 11 = 0

3 x^{2} - 8 x + 5 = 5 x^{2}

x^{2} + 3 - 4 = 0

- x^{2} + 10 x = 0

What are the solutions to the equation x^2-2(x-1)=0 ?
The solutions to the equation x^2-2(x-1)=0 are x=1+i,x=1-i
Find the zeros of x^2-2(x-1)=0
The zeros of x^2-2(x-1)=0 are x=1+i,x=1-i