What are the solutions to the equation completesquare x^2+17x ?

The solutions to the equation completesquare x^2+17x are (x+17/2)^2-289/4

Find the zeros of completesquare x^2+17x

The zeros of completesquare x^2+17x are (x+17/2)^2-289/4

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complete the square

x^{2} + 17 x

(x + \frac{17}{2})^{2} - \frac{289}{4}

Solution steps

x^{2} + 17 x

Write

x^{2} + 17 x

in the form:

x^{2} + 2 a x + a^{2}

2 a = 17 : a = \frac{17}{2}

Add and subtract

(\frac{17}{2})^{2}

x^{2} + 17 x + (\frac{17}{2})^{2} - (\frac{17}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 17 x + (\frac{17}{2})^{2} = (x + \frac{17}{2})^{2}

(x + \frac{17}{2})^{2} - (\frac{17}{2})^{2}

Simplify

(x + \frac{17}{2})^{2} - \frac{289}{4}

- 3 x^{2} - 18 x = 0

1 - 2 x - x^{2} = 0

- 6 x^{2} + 84 x - 240 = 0

4 x^{2} - 10 x - 6 = 0

x^{2} - 1.3 x + 0.3 = 0

What are the solutions to the equation completesquare x^2+17x ?
The solutions to the equation completesquare x^2+17x are (x+17/2)^2-289/4
Find the zeros of completesquare x^2+17x
The zeros of completesquare x^2+17x are (x+17/2)^2-289/4