What are the solutions to the equation 3x^2+30x-27=6 ?

The solutions to the equation 3x^2+30x-27=6 are x=1,x=-11

Find the zeros of 3x^2+30x-27=6

The zeros of 3x^2+30x-27=6 are x=1,x=-11

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3 x^{2} + 30 x - 27 = 6

x = 1, x = - 11

Solution steps

3 x^{2} + 30 x - 27 = 6

Move

6

to the left side

3 x^{2} + 30 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 3 ( - 33 )}{2 \cdot 3}

3 0^{2} - 4 \cdot 3 (- 33) = 36

x_{1, 2} = \frac{- 30 \pm 36}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 30 + 36}{2 \cdot 3}, x_{2} = \frac{- 30 - 36}{2 \cdot 3}

x = \frac{- 30 + 36}{2 \cdot 3} : 1

x = \frac{- 30 - 36}{2 \cdot 3} : - 11

The solutions to the quadratic equation are:

x = 1, x = - 11

x^{2} = - 2 x + 15

3 x^{2} = 13

x^{2} + 23 x + 131 = 5 x - 3

6 x^{2} - 2 x - 6 = 0

(x - 3)^{2} = \frac{x}{4}

What are the solutions to the equation 3x^2+30x-27=6 ?
The solutions to the equation 3x^2+30x-27=6 are x=1,x=-11
Find the zeros of 3x^2+30x-27=6
The zeros of 3x^2+30x-27=6 are x=1,x=-11