What are the solutions to the equation x^2+13=1 ?

The solutions to the equation x^2+13=1 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of x^2+13=1

The zeros of x^2+13=1 are x=2sqrt(3)i,x=-2sqrt(3)i

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x^{2} + 13 = 1

x = 23 i, x = - 23 i

Solution steps

x^{2} + 13 = 1

Move

13

to the right side

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

2 x + 3 \leq - 6 or 2 x + 3 \geq 6

1 - 2 x \leq 4 x + 25

3 x^{2} + 10 x - 77

\frac{4}{16} \cdot \frac{4}{16}

1 - x > 2 x - 2

What are the solutions to the equation x^2+13=1 ?
The solutions to the equation x^2+13=1 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of x^2+13=1
The zeros of x^2+13=1 are x=2sqrt(3)i,x=-2sqrt(3)i