What are the solutions to the equation 9x^2+36x+72=0 ?

The solutions to the equation 9x^2+36x+72=0 are x=-2+2i,x=-2-2i

Find the zeros of 9x^2+36x+72=0

The zeros of 9x^2+36x+72=0 are x=-2+2i,x=-2-2i

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9 x^{2} + 36 x + 72 = 0

x = - 2 + 2 i, x = - 2 - 2 i

Solution steps

9 x^{2} + 36 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 9 \cdot 72}{2 \cdot 9}

Simplify

3 6^{2} - 4 \cdot 9 \cdot 72 : 36 i

x_{1, 2} = \frac{- 36 \pm 36 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 36 + 36 i}{2 \cdot 9}, x_{2} = \frac{- 36 - 36 i}{2 \cdot 9}

x = \frac{- 36 + 36 i}{2 \cdot 9} : - 2 + 2 i

x = \frac{- 36 - 36 i}{2 \cdot 9} : - 2 - 2 i

The solutions to the quadratic equation are:

x = - 2 + 2 i, x = - 2 - 2 i

x, y^{2} + x^{2} = 0

8 x^{2} + 10 x = - 3

3 x^{2} - 6 x = 2

x^{2} + 2 + 1 = 0

6 (x^{2} - x) = x - 2

What are the solutions to the equation 9x^2+36x+72=0 ?
The solutions to the equation 9x^2+36x+72=0 are x=-2+2i,x=-2-2i
Find the zeros of 9x^2+36x+72=0
The zeros of 9x^2+36x+72=0 are x=-2+2i,x=-2-2i