What are the solutions to the equation 9x^2+12x=-4 ?

The solutions to the equation 9x^2+12x=-4 are x=-2/3

Find the zeros of 9x^2+12x=-4

The zeros of 9x^2+12x=-4 are x=-2/3

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9 x^{2} + 12 x = - 4

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

9 x^{2} + 12 x = - 4

Move

4

to the left side

9 x^{2} + 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 9}

x = \frac{- 12}{2 \cdot 9}

\frac{- 12}{2 \cdot 9} = - \frac{2}{3}

x = - \frac{2}{3}

The solution to the quadratic equation is:

x = - \frac{2}{3}

2 x^{2} + 4 x + 0 = 0

0 = 12 x^{2}

x^{2} = \frac{121}{9}

4 x = x^{2} + 1

x^{2} + \frac{1}{4} x + 1 = 0

What are the solutions to the equation 9x^2+12x=-4 ?
The solutions to the equation 9x^2+12x=-4 are x=-2/3
Find the zeros of 9x^2+12x=-4
The zeros of 9x^2+12x=-4 are x=-2/3