What are the solutions to the equation p^2-2p-14=-6 ?

The solutions to the equation p^2-2p-14=-6 are p=4,p=-2

Find the zeros of p^2-2p-14=-6

The zeros of p^2-2p-14=-6 are p=4,p=-2

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p^{2} - 2 p - 14 = - 6

p = 4, p = - 2

Solution steps

p^{2} - 2 p - 14 = - 6

Move

6

to the left side

p^{2} - 2 p - 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

p_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, p_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

p = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

p = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

p = 4, p = - 2

k^{2} + 7 k + 10 = 0

20 x^{2} - 15 x - 10 = 0

4 x^{2} + 4 x + 10 = 0

- 3 x^{2} + 4 x + 2 = 0

x^{2} - 13 x - 30 = 0

What are the solutions to the equation p^2-2p-14=-6 ?
The solutions to the equation p^2-2p-14=-6 are p=4,p=-2
Find the zeros of p^2-2p-14=-6
The zeros of p^2-2p-14=-6 are p=4,p=-2