What are the solutions to the equation 90=x(2x+8) ?

The solutions to the equation 90=x(2x+8) are x=5,x=-9

Find the zeros of 90=x(2x+8)

The zeros of 90=x(2x+8) are x=5,x=-9

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90 = x (2 x + 8)

x = 5, x = - 9

Solution steps

90 = x (2 x + 8)

Expand

x (2 x + 8) : 2 x^{2} + 8 x

90 = 2 x^{2} + 8 x

Switch sides

2 x^{2} + 8 x = 90

Move

90

to the left side

2 x^{2} + 8 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 90 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 90) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 2}, x_{2} = \frac{- 8 - 28}{2 \cdot 2}

x = \frac{- 8 + 28}{2 \cdot 2} : 5

x = \frac{- 8 - 28}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

\frac{n}{12} = - 6

- 3 x^{2} + 5 x - 4 = 0

6 x - 6 = 15 x + 15

2 lo g_{6} (u) - 8 lo g_{6} (v)

2 x + 14 - 6 \geq 4

What are the solutions to the equation 90=x(2x+8) ?
The solutions to the equation 90=x(2x+8) are x=5,x=-9
Find the zeros of 90=x(2x+8)
The zeros of 90=x(2x+8) are x=5,x=-9