What are the solutions to the equation x^2-x-17=3 ?

The solutions to the equation x^2-x-17=3 are x=5,x=-4

Find the zeros of x^2-x-17=3

The zeros of x^2-x-17=3 are x=5,x=-4

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x^{2} - x - 17 = 3

x = 5, x = - 4

Solution steps

x^{2} - x - 17 = 3

Move

3

to the left side

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

x, z = 3 x^{2} + x y - 2 y^{2}

x, x^{2} + y^{2} + 2 x - 3 y + 6 = 0

(x + 5) (x + 2) + 2 = 0

x^{2} + 6 x + 8 = 0

2 x^{2} - 12 = 2 x

What are the solutions to the equation x^2-x-17=3 ?
The solutions to the equation x^2-x-17=3 are x=5,x=-4
Find the zeros of x^2-x-17=3
The zeros of x^2-x-17=3 are x=5,x=-4