What are the solutions to the equation 9m^2+6m+1=0 ?

The solutions to the equation 9m^2+6m+1=0 are m=-1/3

Find the zeros of 9m^2+6m+1=0

The zeros of 9m^2+6m+1=0 are m=-1/3

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9 m^{2} + 6 m + 1 = 0

m = - \frac{1}{3}

Decimal Notation

m = - 0.33333 \dots

Solution steps

9 m^{2} + 6 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

m_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

m = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

m = - \frac{1}{3}

The solution to the quadratic equation is:

m = - \frac{1}{3}

x, 16 x^{2} + 16 y^{2} + 16 x + 8 y + 5 = 0

4 x^{2} - 10 x - 23 = 0

3 x^{2} - 4 = 11 x

x^{2} + x = 50

x^{2} - 8 x = 7

What are the solutions to the equation 9m^2+6m+1=0 ?
The solutions to the equation 9m^2+6m+1=0 are m=-1/3
Find the zeros of 9m^2+6m+1=0
The zeros of 9m^2+6m+1=0 are m=-1/3