What are the solutions to the equation w^2+15=8w ?

The solutions to the equation w^2+15=8w are w=5,w=3

Find the zeros of w^2+15=8w

The zeros of w^2+15=8w are w=5,w=3

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w^{2} + 15 = 8 w

w = 5, w = 3

Solution steps

w^{2} + 15 = 8 w

Move

8 w

to the left side

w^{2} + 15 - 8 w = 0

Write in the standard form

a x^{2} + b x + c = 0

w^{2} - 8 w + 15 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

w_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, w_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

w = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

w = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

w = 5, w = 3

x, y^{2} - 4 x y + 4 x^{2} = 0

x^{2} + 3 x + 2 = 0

A x^{2} + B x + C = 0

x^{2} - 11 x + 5 = - 6 x + 5 - 6 x + 5

2 0^{2} + b^{2} = 2 5^{2}

What are the solutions to the equation w^2+15=8w ?
The solutions to the equation w^2+15=8w are w=5,w=3
Find the zeros of w^2+15=8w
The zeros of w^2+15=8w are w=5,w=3