What are the solutions to the equation 7x^2-3x=1 ?

The solutions to the equation 7x^2-3x=1 are x=(3+sqrt(37))/(14),x=(3-sqrt(37))/(14)

Find the zeros of 7x^2-3x=1

The zeros of 7x^2-3x=1 are x=(3+sqrt(37))/(14),x=(3-sqrt(37))/(14)

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7 x^{2} - 3 x = 1

x = \frac{3 + 37}{14}, x = \frac{3 - 37}{14}

Decimal Notation

x = 0.64876 \dots, x = - 0.22019 \dots

Solution steps

7 x^{2} - 3 x = 1

Move

1

to the left side

7 x^{2} - 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 (- 1) = 37

x_{1, 2} = \frac{- ( - 3 ) \pm 37}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 37}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 37}{2 \cdot 7}

x = \frac{- ( - 3 ) + 37}{2 \cdot 7} : \frac{3 + 37}{14}

x = \frac{- ( - 3 ) - 37}{2 \cdot 7} : \frac{3 - 37}{14}

The solutions to the quadratic equation are:

x = \frac{3 + 37}{14}, x = \frac{3 - 37}{14}

- x^{2} - 5 x + 4 = 0

m^{2} - 3 = 0

x^{2} - a x

x, x^{2} + 2 x - 8 = 0

(3 - x)^{2} - 1 = 0

What are the solutions to the equation 7x^2-3x=1 ?
The solutions to the equation 7x^2-3x=1 are x=(3+sqrt(37))/(14),x=(3-sqrt(37))/(14)
Find the zeros of 7x^2-3x=1
The zeros of 7x^2-3x=1 are x=(3+sqrt(37))/(14),x=(3-sqrt(37))/(14)