What are the solutions to the equation 3x^2+4x=0 ?

The solutions to the equation 3x^2+4x=0 are x=0,x=-4/3

Find the zeros of 3x^2+4x=0

The zeros of 3x^2+4x=0 are x=0,x=-4/3

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3 x^{2} + 4 x = 0

x = 0, x = - \frac{4}{3}

Decimal Notation

x = 0, x = - 1.33333 \dots

Solution steps

3 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

4^{2} - 4 \cdot 3 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 3}, x_{2} = \frac{- 4 - 4}{2 \cdot 3}

x = \frac{- 4 + 4}{2 \cdot 3} : 0

x = \frac{- 4 - 4}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{3}

\frac{2}{3} - \frac{1}{4} + \frac{2}{5}

e^{4 l n (5)}

- 2.5 x = 20.5

6 x^{2} + 5 x < 4

x^{3} - 20 x^{2} + 100 x

What are the solutions to the equation 3x^2+4x=0 ?
The solutions to the equation 3x^2+4x=0 are x=0,x=-4/3
Find the zeros of 3x^2+4x=0
The zeros of 3x^2+4x=0 are x=0,x=-4/3