What are the solutions to the equation 12x^2-36x+20=0 ?

The solutions to the equation 12x^2-36x+20=0 are x=(9+sqrt(21))/6 ,x=(9-sqrt(21))/6

Find the zeros of 12x^2-36x+20=0

The zeros of 12x^2-36x+20=0 are x=(9+sqrt(21))/6 ,x=(9-sqrt(21))/6

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12 x^{2} - 36 x + 20 = 0

x = \frac{9 + 21}{6}, x = \frac{9 - 21}{6}

Decimal

x = 2.26376 \dots, x = 0.73623 \dots

Solution steps

12 x^{2} - 36 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 12 \cdot 20}{2 \cdot 12}

(- 36)^{2} - 4 \cdot 12 \cdot 20 = 421

x_{1, 2} = \frac{- ( - 36 ) \pm 4 21}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 4 21}{2 \cdot 12}, x_{2} = \frac{- ( - 36 ) - 4 21}{2 \cdot 12}

x = \frac{- ( - 36 ) + 4 21}{2 \cdot 12} : \frac{9 + 21}{6}

x = \frac{- ( - 36 ) - 4 21}{2 \cdot 12} : \frac{9 - 21}{6}

The solutions to the quadratic equation are:

x = \frac{9 + 21}{6}, x = \frac{9 - 21}{6}

- 24 x^{2} + 6 = 0

n^{2} - 8 n + 66 = 2

x^{2} + 2 = 1

q^{2} + 3 q - 18 = 0

3 x^{2} - 20 x = 32

What are the solutions to the equation 12x^2-36x+20=0 ?
The solutions to the equation 12x^2-36x+20=0 are x=(9+sqrt(21))/6 ,x=(9-sqrt(21))/6
Find the zeros of 12x^2-36x+20=0
The zeros of 12x^2-36x+20=0 are x=(9+sqrt(21))/6 ,x=(9-sqrt(21))/6