What are the solutions to the equation 5n^2+19n-68=-2 ?

The solutions to the equation 5n^2+19n-68=-2 are n= 11/5 ,n=-6

Find the zeros of 5n^2+19n-68=-2

The zeros of 5n^2+19n-68=-2 are n= 11/5 ,n=-6

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5 n^{2} + 19 n - 68 = - 2

n = \frac{11}{5}, n = - 6

Decimal Notation

n = 2.2, n = - 6

Solution steps

5 n^{2} + 19 n - 68 = - 2

Move

2

to the left side

5 n^{2} + 19 n - 66 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 5 ( - 66 )}{2 \cdot 5}

1 9^{2} - 4 \cdot 5 (- 66) = 41

n_{1, 2} = \frac{- 19 \pm 41}{2 \cdot 5}

Separate the solutions

n_{1} = \frac{- 19 + 41}{2 \cdot 5}, n_{2} = \frac{- 19 - 41}{2 \cdot 5}

n = \frac{- 19 + 41}{2 \cdot 5} : \frac{11}{5}

n = \frac{- 19 - 41}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

n = \frac{11}{5}, n = - 6

3 x^{2} + 6 x + 78 = 0

0 = - 2 x^{2} + 8 x

p, p^{2} + 2 pq + q^{2} = 1

10 x^{2} - 6 x - 7 = 4 x^{2} + 7 x - 2

6 x^{2} + 84 = 0

What are the solutions to the equation 5n^2+19n-68=-2 ?
The solutions to the equation 5n^2+19n-68=-2 are n= 11/5 ,n=-6
Find the zeros of 5n^2+19n-68=-2
The zeros of 5n^2+19n-68=-2 are n= 11/5 ,n=-6