What are the solutions to the equation 3x^2-6x+24=0 ?

The solutions to the equation 3x^2-6x+24=0 are x=1+sqrt(7)i,x=1-sqrt(7)i

Find the zeros of 3x^2-6x+24=0

The zeros of 3x^2-6x+24=0 are x=1+sqrt(7)i,x=1-sqrt(7)i

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3 x^{2} - 6 x + 24 = 0

x = 1 + 7 i, x = 1 - 7 i

Solution steps

3 x^{2} - 6 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 24 : 67 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 7 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 7 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 7 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 7 i}{2 \cdot 3} : 1 + 7 i

x = \frac{- ( - 6 ) - 6 7 i}{2 \cdot 3} : 1 - 7 i

The solutions to the quadratic equation are:

x = 1 + 7 i, x = 1 - 7 i

(x - 6)^{2} - 8 x = 0

0 = \frac{2}{3} (x - 1) (x + 3)

x, x^{2} - 3 x - 10 = 0

x, x^{2} - 3 x - 4 = 0

\frac{3 ^{3} x ^{2} + 100}{3} = 0

What are the solutions to the equation 3x^2-6x+24=0 ?
The solutions to the equation 3x^2-6x+24=0 are x=1+sqrt(7)i,x=1-sqrt(7)i
Find the zeros of 3x^2-6x+24=0
The zeros of 3x^2-6x+24=0 are x=1+sqrt(7)i,x=1-sqrt(7)i