What are the solutions to the equation 2(x+5)^2-6=-1 ?

The solutions to the equation 2(x+5)^2-6=-1 are x=sqrt(5/2)-5,x=-sqrt(5/2)-5

Find the zeros of 2(x+5)^2-6=-1

The zeros of 2(x+5)^2-6=-1 are x=sqrt(5/2)-5,x=-sqrt(5/2)-5

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2 (x + 5)^{2} - 6 = - 1

x = \frac{5}{2} - 5, x = - \frac{5}{2} - 5

Decimal Notation

x = - 3.41886 \dots, x = - 6.58113 \dots

Solution steps

2 (x + 5)^{2} - 6 = - 1

Move

6

to the right side

2 (x + 5)^{2} = 5

Divide both sides by

2

(x + 5)^{2} = \frac{5}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = \frac{5}{2} : x = \frac{5}{2} - 5

Solve

x + 5 = - \frac{5}{2} : x = - \frac{5}{2} - 5

The solutions to the quadratic equation are:

x = \frac{5}{2} - 5, x = - \frac{5}{2} - 5

x - 2 = x^{2} - x - 6

x, (x - y)^{2} = x + y - 1

(x - 5) (x - 3) = 0

4 x^{2} + 20 = - 220

x^{2} + 4 = 19

What are the solutions to the equation 2(x+5)^2-6=-1 ?
The solutions to the equation 2(x+5)^2-6=-1 are x=sqrt(5/2)-5,x=-sqrt(5/2)-5
Find the zeros of 2(x+5)^2-6=-1
The zeros of 2(x+5)^2-6=-1 are x=sqrt(5/2)-5,x=-sqrt(5/2)-5