What are the solutions to the equation (4x+7)(x-1)=2(x-1) ?

The solutions to the equation (4x+7)(x-1)=2(x-1) are x=1,x=-5/4

Find the zeros of (4x+7)(x-1)=2(x-1)

The zeros of (4x+7)(x-1)=2(x-1) are x=1,x=-5/4

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(4 x + 7) (x - 1) = 2 (x - 1)

x = 1, x = - \frac{5}{4}

Decimal Notation

x = 1, x = - 1.25

Solution steps

(4 x + 7) (x - 1) = 2 (x - 1)

Move

2 (x - 1)

to the left side

(4 x + 7) (x - 1) - 2 (x - 1) = 0

Factor

(4 x + 7) (x - 1) - 2 (x - 1) : (x - 1) (4 x + 5)

(x - 1) (4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 4 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{4}

- 8 x + 19 = - 2 x^{2}

3 x^{2} - 10 = - 85

(x + 1)^{2} = - 18

(r + 5)^{2} + (r - 2)^{2} = 37

24 x^{2} + 114 x + 132 = 0

What are the solutions to the equation (4x+7)(x-1)=2(x-1) ?
The solutions to the equation (4x+7)(x-1)=2(x-1) are x=1,x=-5/4
Find the zeros of (4x+7)(x-1)=2(x-1)
The zeros of (4x+7)(x-1)=2(x-1) are x=1,x=-5/4