What are the solutions to the equation 0=x^2+8x-9 ?

The solutions to the equation 0=x^2+8x-9 are x=1,x=-9

Find the zeros of 0=x^2+8x-9

The zeros of 0=x^2+8x-9 are x=1,x=-9

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0 = x^{2} + 8 x - 9

x = 1, x = - 9

Solution steps

0 = x^{2} + 8 x - 9

Switch sides

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

\frac{1}{2} x^{2} = 49

- 6 x^{2} + 60 x - 126 = 0

x^{2} + 7 x + 12 = 0

z^{2} = - 25

16 x^{2} + 16 x + 1 = 0

What are the solutions to the equation 0=x^2+8x-9 ?
The solutions to the equation 0=x^2+8x-9 are x=1,x=-9
Find the zeros of 0=x^2+8x-9
The zeros of 0=x^2+8x-9 are x=1,x=-9