What are the solutions to the equation 4x^2-4x+10=0 ?

The solutions to the equation 4x^2-4x+10=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2

Find the zeros of 4x^2-4x+10=0

The zeros of 4x^2-4x+10=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2

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4 x^{2} - 4 x + 10 = 0

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

4 x^{2} - 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 10 : 12 i

x_{1, 2} = \frac{- ( - 4 ) \pm 12 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 12 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 12 i}{2 \cdot 4} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 4 ) - 12 i}{2 \cdot 4} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

3 - 4 x + x^{2} = 0

4 x^{2} - 17 x = - 4

x^{2} + \frac{5 x}{12} - \frac{1}{6} = 0

75 = x^{2}

12 x^{2} + 7 x - 10 = 0

What are the solutions to the equation 4x^2-4x+10=0 ?
The solutions to the equation 4x^2-4x+10=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2
Find the zeros of 4x^2-4x+10=0
The zeros of 4x^2-4x+10=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2