What are the solutions to the equation completesquare x^2+4x-5=0 ?

The solutions to the equation completesquare x^2+4x-5=0 are x=1,x=-5

Find the zeros of completesquare x^2+4x-5=0

The zeros of completesquare x^2+4x-5=0 are x=1,x=-5

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x^{2} + 4 x - 5 = 0

x = 1, x = - 5

Solution steps

x^{2} + 4 x - 5 = 0

Move

5

to the right side

x^{2} + 4 x = 5

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 9

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 9 : x = 1

Solve

x + 2 = - 9 : x = - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

2 x^{2} = - 28 x - 80

- 3 x^{2} - 6 x + 7

- 21 = 15 - 2 x^{2}

x^{2} + 4 x - 2 = 0

- 5 + x^{2} = - 4 x

What are the solutions to the equation completesquare x^2+4x-5=0 ?
The solutions to the equation completesquare x^2+4x-5=0 are x=1,x=-5
Find the zeros of completesquare x^2+4x-5=0
The zeros of completesquare x^2+4x-5=0 are x=1,x=-5