What are the solutions to the equation 9^2+4^2=c^2 ?

The solutions to the equation 9^2+4^2=c^2 are c=sqrt(97),c=-sqrt(97)

Find the zeros of 9^2+4^2=c^2

The zeros of 9^2+4^2=c^2 are c=sqrt(97),c=-sqrt(97)

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9^{2} + 4^{2} = c^{2}

c = 97, c = - 97

Decimal Notation

c = 9.84885 \dots, c = - 9.84885 \dots

Solution steps

9^{2} + 4^{2} = c^{2}

Switch sides

c^{2} = 9^{2} + 4^{2}

Simplify

9^{2} + 4^{2} : 97

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 97, c = - 97

x^{2} + 9 x^{2} - x - 9 = 0

x, \frac{( y _{2} )}{2} - \frac{( ( x + 2 ) ^{2} )}{4} = 1

x, 9 x^{2} + y^{2} - 9 z^{2} - 54 x - 4 y - 54 z + 4 = 0

3 x^{2} + 11 x - 7 = 0

A = x^{2} + x - 2

What are the solutions to the equation 9^2+4^2=c^2 ?
The solutions to the equation 9^2+4^2=c^2 are c=sqrt(97),c=-sqrt(97)
Find the zeros of 9^2+4^2=c^2
The zeros of 9^2+4^2=c^2 are c=sqrt(97),c=-sqrt(97)