What are the solutions to the equation 8x^2-5x+3=0 ?

The solutions to the equation 8x^2-5x+3=0 are x= 5/16+i(sqrt(71))/(16),x= 5/16-i(sqrt(71))/(16)

Find the zeros of 8x^2-5x+3=0

The zeros of 8x^2-5x+3=0 are x= 5/16+i(sqrt(71))/(16),x= 5/16-i(sqrt(71))/(16)

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8 x^{2} - 5 x + 3 = 0

x = \frac{5}{16} + i \frac{71}{16}, x = \frac{5}{16} - i \frac{71}{16}

Solution steps

8 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 8 \cdot 3}{2 \cdot 8}

Simplify

(- 5)^{2} - 4 \cdot 8 \cdot 3 : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 8}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 8}

x = \frac{- ( - 5 ) + 71 i}{2 \cdot 8} : \frac{5}{16} + i \frac{71}{16}

x = \frac{- ( - 5 ) - 71 i}{2 \cdot 8} : \frac{5}{16} - i \frac{71}{16}

The solutions to the quadratic equation are:

x = \frac{5}{16} + i \frac{71}{16}, x = \frac{5}{16} - i \frac{71}{16}

x^{2} - 3 x + 2 = 0

- 5 x^{2} + 12 x + 7 = 0

6 x^{2} + x - 8 = 0

(x + 8)^{2} = 16 - x^{2} + 9 x

3600 + 25 x + \frac{1}{2} x^{2} = (175 - \frac{1}{2} x) x

What are the solutions to the equation 8x^2-5x+3=0 ?
The solutions to the equation 8x^2-5x+3=0 are x= 5/16+i(sqrt(71))/(16),x= 5/16-i(sqrt(71))/(16)
Find the zeros of 8x^2-5x+3=0
The zeros of 8x^2-5x+3=0 are x= 5/16+i(sqrt(71))/(16),x= 5/16-i(sqrt(71))/(16)