What are the solutions to the equation t^2+6t+5=0 ?

The solutions to the equation t^2+6t+5=0 are t=-1,t=-5

Find the zeros of t^2+6t+5=0

The zeros of t^2+6t+5=0 are t=-1,t=-5

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t^{2} + 6 t + 5 = 0

t = - 1, t = - 5

Solution steps

t^{2} + 6 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

t_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 6 + 4}{2 \cdot 1}, t_{2} = \frac{- 6 - 4}{2 \cdot 1}

t = \frac{- 6 + 4}{2 \cdot 1} : - 1

t = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

t = - 1, t = - 5

z^{2} - 6 z

z^{2} + 8 z

z^{2} + 2 z

b^{2} = 25

- x^{2} + 8 x + 3 = 0

What are the solutions to the equation t^2+6t+5=0 ?
The solutions to the equation t^2+6t+5=0 are t=-1,t=-5
Find the zeros of t^2+6t+5=0
The zeros of t^2+6t+5=0 are t=-1,t=-5