What are the solutions to the equation 3x^2-8=-10x ?

The solutions to the equation 3x^2-8=-10x are x= 2/3 ,x=-4

Find the zeros of 3x^2-8=-10x

The zeros of 3x^2-8=-10x are x= 2/3 ,x=-4

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3 x^{2} - 8 = - 10 x

x = \frac{2}{3}, x = - 4

Decimal Notation

x = 0.66666 \dots, x = - 4

Solution steps

3 x^{2} - 8 = - 10 x

Move

10 x

to the left side

3 x^{2} - 8 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 8) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 3}, x_{2} = \frac{- 10 - 14}{2 \cdot 3}

x = \frac{- 10 + 14}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 10 - 14}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 4

20 x^{2} + 23 x + 6 = 0

x (2 x + 1) - 5 (x - 2) = 6

(3 x + 1) (3 x - 1) + x = 4 x^{2} - 3

15 x^{2} = 90 x

5 x^{2} + 8 x - 23 = 0

What are the solutions to the equation 3x^2-8=-10x ?
The solutions to the equation 3x^2-8=-10x are x= 2/3 ,x=-4
Find the zeros of 3x^2-8=-10x
The zeros of 3x^2-8=-10x are x= 2/3 ,x=-4