What are the solutions to the equation (3x+4)^2=24x+16 ?

The solutions to the equation (3x+4)^2=24x+16 are x=0

Find the zeros of (3x+4)^2=24x+16

The zeros of (3x+4)^2=24x+16 are x=0

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(3 x + 4)^{2} = 24 x + 16

x = 0

Solution steps

(3 x + 4)^{2} = 24 x + 16

Expand

(3 x + 4)^{2} : 9 x^{2} + 24 x + 16

9 x^{2} + 24 x + 16 = 24 x + 16

Move

16

to the right side

9 x^{2} + 24 x = 24 x

Move

24 x

to the left side

9 x^{2} = 0

Divide both sides by

9

x = 0

3 x^{2} + x = 1

3 x^{2} - 7 x - 13 = 0

5 x^{2} - 2 x + 12 = 0

x^{2} + 4 = - 6 x

a^{2} - 16 = 0

What are the solutions to the equation (3x+4)^2=24x+16 ?
The solutions to the equation (3x+4)^2=24x+16 are x=0
Find the zeros of (3x+4)^2=24x+16
The zeros of (3x+4)^2=24x+16 are x=0