What are the solutions to the equation 16((x+6)/4)^2+8((x+6)/4)+1=0 ?

The solutions to the equation 16((x+6)/4)^2+8((x+6)/4)+1=0 are x=-7

Find the zeros of 16((x+6)/4)^2+8((x+6)/4)+1=0

The zeros of 16((x+6)/4)^2+8((x+6)/4)+1=0 are x=-7

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16 (\frac{x + 6}{4})^{2} + 8 (\frac{x + 6}{4}) + 1 = 0

x = - 7

Solution steps

16 (\frac{x + 6}{4})^{2} + 8 (\frac{x + 6}{4}) + 1 = 0

Expand

16 (\frac{x + 6}{4})^{2} + 8 (\frac{x + 6}{4}) + 1 : x^{2} + 14 x + 49

x^{2} + 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

x = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

x = - 7

The solution to the quadratic equation is:

x = - 7

4 = \frac{b ^{2}}{3}

3 x^{2} + 324 = 0

3 x^{2} - 8 x = - 4

λ^{2} + λ - 2 = 0

3 x^{2} + 44 x = 0

What are the solutions to the equation 16((x+6)/4)^2+8((x+6)/4)+1=0 ?
The solutions to the equation 16((x+6)/4)^2+8((x+6)/4)+1=0 are x=-7
Find the zeros of 16((x+6)/4)^2+8((x+6)/4)+1=0
The zeros of 16((x+6)/4)^2+8((x+6)/4)+1=0 are x=-7