What are the solutions to the equation x^2+8x+15=48 ?

The solutions to the equation x^2+8x+15=48 are x=3,x=-11

Find the zeros of x^2+8x+15=48

The zeros of x^2+8x+15=48 are x=3,x=-11

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x^{2} + 8 x + 15 = 48

x = 3, x = - 11

Solution steps

x^{2} + 8 x + 15 = 48

Move

48

to the left side

x^{2} + 8 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 33 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 33) = 14

x_{1, 2} = \frac{- 8 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 14}{2 \cdot 1}, x_{2} = \frac{- 8 - 14}{2 \cdot 1}

x = \frac{- 8 + 14}{2 \cdot 1} : 3

x = \frac{- 8 - 14}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 3, x = - 11

8 x^{2} - 16 = 0

x^{2} - 9 x + 14

2 x^{2} + 31 = 4 x^{2} - 19

w^{2} - 18 w + 56 = 0

x, 25 x^{2} + y^{2} - 100 x + 6 y + 190 = 0

What are the solutions to the equation x^2+8x+15=48 ?
The solutions to the equation x^2+8x+15=48 are x=3,x=-11
Find the zeros of x^2+8x+15=48
The zeros of x^2+8x+15=48 are x=3,x=-11