What are the solutions to the equation (3x+2)^2=12 ?

The solutions to the equation (3x+2)^2=12 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3

Find the zeros of (3x+2)^2=12

The zeros of (3x+2)^2=12 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x + 2)^{2} = 12

x = \frac{2 3 - 2}{3}, x = \frac{- 2 3 - 2}{3}

Decimal Notation

x = 0.48803 \dots, x = - 1.82136 \dots

Solution steps

(3 x + 2)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 12 : x = \frac{2 3 - 2}{3}

Solve

3 x + 2 = - 12 : x = \frac{- 2 3 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{2 3 - 2}{3}, x = \frac{- 2 3 - 2}{3}

- x^{2} + x = - 6

550 = 450 (1 + x)^{2}

25 x^{2} + 10 x - 4 = 0

4 x^{2} - 9 = 71

7 x^{2} - 6 x + 6 = 0

What are the solutions to the equation (3x+2)^2=12 ?
The solutions to the equation (3x+2)^2=12 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3
Find the zeros of (3x+2)^2=12
The zeros of (3x+2)^2=12 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3