What is 1/(x+1)> 2/(x-1) ?

The solution to 1/(x+1)> 2/(x-1) is x<-3\lor-1<x<1

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1/(x+1)> 2/(x-1)

\frac{1}{x + 1} > \frac{2}{x - 1}

x < - 3 or - 1 < x < 1

Interval Notation

(- \infty, - 3) \cup (- 1, 1)

Solution steps

\frac{1}{x + 1} > \frac{2}{x - 1}

Rewrite in standard form

\frac{- x - 3}{( x + 1 ) ( x - 1 )} > 0

Identify the intervals

x < - 3 or - 1 < x < 1

ab + ah

30 \cdot \frac{π}{180}

(4 - 6 i)^{2}

10 \cdot 8

∣ x + 6 ∣ > 4