What are the solutions to the equation (x^2-7)2+2x^2-14=0 ?

The solutions to the equation (x^2-7)2+2x^2-14=0 are x=sqrt(7),x=-sqrt(7)

Find the zeros of (x^2-7)2+2x^2-14=0

The zeros of (x^2-7)2+2x^2-14=0 are x=sqrt(7),x=-sqrt(7)

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(x^{2} - 7) 2 + 2 x^{2} - 14 = 0

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

(x^{2} - 7) \cdot 2 + 2 x^{2} - 14 = 0

Move

14

to the right side

(x^{2} - 7) \cdot 2 + 2 x^{2} = 14

Expand

(x^{2} - 7) \cdot 2 + 2 x^{2} : 4 x^{2} - 14

4 x^{2} - 14 = 14

Move

14

to the right side

4 x^{2} = 28

Divide both sides by

4

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

- x^{2} - 9 x = 0

x, - \frac{1}{4} x^{2} + \frac{1}{2} x + \frac{1}{2} = 0

(x - 4) (x + 8) = 0

m^{2} - 3 m

x^{2} + 4 x - 8.25 = 0

What are the solutions to the equation (x^2-7)2+2x^2-14=0 ?
The solutions to the equation (x^2-7)2+2x^2-14=0 are x=sqrt(7),x=-sqrt(7)
Find the zeros of (x^2-7)2+2x^2-14=0
The zeros of (x^2-7)2+2x^2-14=0 are x=sqrt(7),x=-sqrt(7)